As has been already mentioned, it's not useful to look at the absolute peak MAP/MAF value (i.e. at the torque peak) when comparing the OE vs Colt cams and the respective timing variations due to sensor saturation. More useful would be to superimpose all the curves on common axes and look for differences in MAF mg/stroke away from this saturation area, at the same given RPM to give insight of the volumetric efficiency. By eyeballing across several graphs, they look very similar, but putting them all on a single one will show more clearly what if any differences the cams and timings have.
Another graph can be generated for the actual volumetric efficiency - since there are also MAP and IAT logs, we can find the density.
The volumetric efficiency is then mass flow [kg/stroke] / (density[kg/m³] * 0.25 * displacement[m³]). The factor 0.25 is because only one cylinder is having an intake event per stroke.
Picking out a convenient data point for eyeballing, I chose the Colt standard at 4250 RPM:
MAF: 900 mg/stroke = 0.0009 kg/stroke
MAP_actual: 3050 mbar = 305000 Pa
IAT (R1, just guessing at 9 sec corresponding to 4250 RPM in the other graphs): 45°C = 318 K
Density = P/RT = 3.34 kg/m³
Displacement = 1896 cm³ = 0.001896 m³
Volumetric efficiency = 0.0009 / (3.34 * 0.25 * 0.001896) = 0.568 = 56.8%
This all assumes of course perfect sensors and measurements, which they are not; there is the possibility for considerable error, so a value of 56.8% should not be judged in isolation but rather compared across other data sets, in statistically significant sampling and against what can be found in the literature.
Edit: I must note that the MAF readings seem to be saturated in the higher RPMs too, because of the hyperbolic shape of the curve - just like a torque curve with constant HP @ increasing RPM will also have a hyperbolic shape. Physically, this makes sense - the MAF measures a time averaged-heat loss from the hot-film and then the ECU takes this analog data, then transforms and discretizes it to RPM to arrive at mg/stroke.